(5x^2-7x+3)=0

Solution for (5x^2-7x+3)=0 equation:

Simplifying
(5x2 + -7x + 3) = 0

Reorder the terms:
(3 + -7x + 5x2) = 0

Remove parenthesis around (3 + -7x + 5x2)
3 + -7x + 5x2 = 0

Solving
3 + -7x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.6 + -1.4x + x2 = 0

Move the constant term to the right:

Add '-0.6' to each side of the equation.
0.6 + -1.4x + -0.6 + x2 = 0 + -0.6

Reorder the terms:
0.6 + -0.6 + -1.4x + x2 = 0 + -0.6

Combine like terms: 0.6 + -0.6 = 0.0
0.0 + -1.4x + x2 = 0 + -0.6
-1.4x + x2 = 0 + -0.6

Combine like terms: 0 + -0.6 = -0.6
-1.4x + x2 = -0.6

The x term is -1.4x.  Take half its coefficient (-0.7).
Square it (0.49) and add it to both sides.

Add '0.49' to each side of the equation.
-1.4x + 0.49 + x2 = -0.6 + 0.49

Reorder the terms:
0.49 + -1.4x + x2 = -0.6 + 0.49

Combine like terms: -0.6 + 0.49 = -0.11
0.49 + -1.4x + x2 = -0.11

Factor a perfect square on the left side:
(x + -0.7)(x + -0.7) = -0.11

Can't calculate square root of the right side.

The solution to this equation could not be determined.